In one tablespoon 15 ml. vinegar. Of them 0.7 * 15 = 10.5 ml. acetic acid and 0.3 * 15 = 4.5 ml. water.

If 10.5 ml. will become 9 percent of the solution, then the water in such a solution should become

91% * 10.5 ml. / 9% = 106.166667

So to this spoon of vinegar

106.1666667 – 4.5 = 101.6666667 ml. water

And everything will turn out

116.666667 ml. 9%vinegar.

However, if you need to calculate only the total volume of the resulting vinegar, you can do it easier:

The tablespoon contains 0.7 * 15 = 10.5 ml. acetic acid and 0.3 * 15 = 4.5 ml. water.

Let’s make a proportion:

10.5 ml. – 9%

X ml. – 100%

X = 10.5 * 100/9 = 116.666667 ml. 9%vinegar will be obtained from one tablespoon of 70%vinegar (or 117 ml., if rounded to the whole).

To calculate the amount of 9% vinegar, which corresponds to one tablespoon of 70% vinegar, you need to use the formula:

(volume 70% vinegar * Acid content in 70% vinegar) / Acid content in 9% vinegar = volume 9% vinegar

Volume 1 tablespoon – 15 ml. Acid in 70% vinegar – 0.7. Acid content in 9% vinegar – 0.09.

We substitute values in the formula:

(15 ml * 0.7) / 0.09 = 116.67 ml

Thus, one tablespoon of 70% vinegar corresponds to 116.67 ml or about 0.12 l 9% vinegar.

If in everyday life, measure the volumes of vinegar 70%acid (essence) and water when dissolved by the latter tablespoons, then to obtain a 9%solution, it is necessary to take 1 tablespoon of essence and dilute approximately eight (7.78 round to 8) table spoonwater. Since the volume of the dining room is 15 ml, the volume of the resulting solution is approximately 15*9 = 135 ml.